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121r^2=64
We move all terms to the left:
121r^2-(64)=0
a = 121; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·121·(-64)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30976}=176$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*121}=\frac{-176}{242} =-8/11 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*121}=\frac{176}{242} =8/11 $
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